Question
Divide. \[ \left(b^{2}-16 b+64\right) \div(b-8) \] \( \square \)
Ask by Henry Davey. in the United States
Feb 27,2025
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Answer
The result is \( b - 8 \).
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Beyond the Answer
To divide \( b^{2} - 16b + 64 \) by \( b - 8 \), we first note that the expression \( b^{2} - 16b + 64 \) can be factored. It factors as: \[ (b - 8)(b - 8) = (b - 8)^{2} \] Now, when we divide \( (b - 8)^{2} \) by \( b - 8 \), we have: \[ \frac{(b - 8)(b - 8)}{b - 8} = b - 8 \] Thus, the result of the division is: \[ \boxed{b - 8} \]