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Question Use the square roots property to solve the quadratic equation \( (y+1)^{2}+58=63 \). If there are multiple answers, list them separated by a comma, e.g. 1,2 . If there is no solution, enter \( \varnothing \).

Ask by Clark Turner. in the United States
Feb 27,2025

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The solutions are: -1+√5, -1-√5.

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The Deep Dive

To solve the equation \( (y+1)^{2}+58=63 \), start by isolating the square term. Subtract 58 from both sides of the equation: \[ (y+1)^{2} = 5 \] Next, apply the square roots property. Take the square root of both sides: \[ y + 1 = \pm \sqrt{5} \] Now, solve for \( y \) by subtracting 1 from both equations: 1. \( y = -1 + \sqrt{5} \) 2. \( y = -1 - \sqrt{5} \) Thus, the solutions are: \[ y = -1 + \sqrt{5}, -1 - \sqrt{5} \]

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