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Multiply and leave your answer in radical form. \( \sqrt[5]{x} \cdot \sqrt[6]{x} \)

Ask by Lambert Wright. in the United States
Feb 27,2025

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The product is \( \sqrt[30]{x^{11}} \).

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To multiply the two expressions \( \sqrt[5]{x} \) and \( \sqrt[6]{x} \), we can rewrite them using exponents. This gives us \( x^{1/5} \cdot x^{1/6} \). When multiplying like bases, we add the exponents. So, we have: \[ x^{1/5 + 1/6} \] To add \( 1/5 \) and \( 1/6 \), we need a common denominator, which is 30. Converting the fractions gives us \( 6/30 + 5/30 = 11/30 \). Thus, we have: \[ x^{11/30} \] Finally, we can express this in radical form: \[ \sqrt[30]{x^{11}} \] So, the final answer is: \[ \sqrt[30]{x^{11}} \]

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