My score: \( 82 / 122 \) pts ( \( 67.21 \% \) ) A set of plans shows that an opening in a bulkhead is needed for a section of pipe to pass through. The plans show metric values, but the only tape measure available is marked in inches. The pipe is shown as a - size DN80 (a European pipe-sizing standard), and a chart indicates the outside diameter of DN80 pipe is 88 millimeters ( mm ). According. to the plans, all openings must be 40 mm larger than the pipe. You know that 25.4 mm is equal to one inch. What is the diameter of the needed opening in inches? Round your answer to the nearest whole inch.
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


Bonus Knowledge
First, let’s calculate the diameter of the opening in millimeters. Since the outside diameter of DN80 pipe is 88 mm, and the opening must be 40 mm larger, we add those values together: \( 88 \, \text{mm} + 40 \, \text{mm} = 128 \, \text{mm} \). Next, convert 128 mm to inches by dividing by 25.4 mm/inch: \( 128 \, \text{mm} ÷ 25.4 \approx 5.04 \, \text{inches} \). Rounding this to the nearest whole inch gives us 5 inches. So, the diameter of the needed opening is approximately **5 inches**. Now, wasn’t that a fun mix of math and measurement conversion? Calculating such dimensions is like piecing together a puzzle where each number contributes to the final picture! Plus, mastering metric-to-imperial conversions can make you feel like a measurement wizard ready to tackle any project that comes your way!