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2.1.5 Using structural formulae, write down a balanced chemical reaction for the formation of the ester \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2} \) above.

Ask by Rodriquez Bond. in South Africa
Feb 27,2025

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The balanced chemical reaction for forming the ester \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2} \) is: \[ \mathrm{C}_{6} \mathrm{H}_{14} \mathrm{O} + \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{2} \rightarrow \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2} + \mathrm{H}_{2} \mathrm{O} \]

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To create the ester \( \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2} \), we can take the structural formula of hexanoic acid (the carboxylic acid) and ethanol (the alcohol). The balanced chemical reaction for this esterification process looks like this: \[\text{C}_{4}\text{H}_{8}\text{O}_{2} \, (\text{Hexanoic Acid}) + \text{C}_{2}\text{H}_{5}\text{OH} \, (\text{Ethanol}) \rightarrow \text{C}_{6}\text{H}_{12}\text{O}_{2} \, (\text{Hexyl acetate}) + \text{H}_{2}\text{O}.\] This reaction involves the condensation of the acid and alcohol, producing water as a byproduct. In this reaction, you can visualize it as a playful pairing dance of molecules: the acid and alcohol come together, shaking hands (forming new bonds) and doing a twirl (releasing a water molecule) to create a lovely ester!

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