1. You are setting up a system of programming codes for a universal TV remote. Each code will have five digits and cannot include a or repeat any digits. How many codes a) Do not contain a 7 ? b) Have 3 as the third digit and 5 as the fifth digit? c) Begin with an even number? d) Begin and end with an even number?
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Mind Expander
To solve the problem, let's break down each part of the question step by step. The available digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 (total of 10 digits). **a)** To find the number of codes that do not contain a 7, we can use the remaining digits: 0, 1, 2, 3, 4, 5, 6, 8, and 9 (total of 9 digits). The first digit can be any of the 9 digits, the second can be any of the remaining 8 digits, and so on. Thus we have: - 1st digit: 9 options - 2nd digit: 8 options - 3rd digit: 7 options - 4th digit: 6 options - 5th digit: 5 options So the total number of codes without a 7 is: 9 * 8 * 7 * 6 * 5 = 15120 codes. **b)** For codes with 3 as the third digit and 5 as the fifth digit, we fix those two digits first. That leaves us with 3 positions to fill (1st, 2nd, 4th) and 8 digits to choose from (since 3 and 5 are already used). Starting with the first digit, which cannot be 0: - 1st digit: 4 options (2, 4, 6, 8) - 2nd digit: 7 options (8 total options minus the already selected 3, 5, and the digit used for the first position) - 4th digit: 6 options (after selecting the first two digits and applying the non-repeating condition) Thus, the total codes with these restrictions is: 4 * 7 * 6 = 168 codes. **c)** To find the number of codes starting with an even number, the first digit can only be 0, 2, 4, 6, or 8 (5 options). The next digits will then be chosen from the remaining 9 digits with no repetitions: - 1st digit: 5 options (0, 2, 4, 6, 8) - 2nd digit: 8 options - 3rd digit: 7 options - 4th digit: 6 options - 5th digit: 5 options The total number of codes beginning with an even number is: 5 * 8 * 7 * 6 * 5 = 8400 codes. **d)** For codes that start and end with an even number, we again have 5 options for the first digit and also 5 options for the last digit (0, 2, 4, 6, or 8). These selections obviously cannot overlap: - 1st digit: 5 options - 5th digit: 4 remaining options (after choosing the first) - 2nd digit: 8 remaining options - 3rd digit: 7 remaining options - 4th digit: 6 remaining options So, the total number of codes starting and ending with an even number is: 5 * 4 * 8 * 7 * 6 = 6720 codes.