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Bereken die som van elk van die volgende reekse: (1) \( 2+\frac{1}{2}+4+\frac{1}{4}+8+\frac{1}{8}+16+\frac{1}{16}+\ldots \) (tot 16 terme) (2) \( 2+3+9+5+16+7+23+9+\ldots \) (tot 25 terme \( ) \) (3) \( 4+8+4+6+4+4+4+2+\ldots \) (tot 30 terme \( ) \) (4) \( \frac{2}{3}-3+2-3+6-3+18-3+\ldots \) (tot 19 terme)

Ask by Salazar Lambert. in South Africa
Jan 31,2025

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Hier is die som van elke reeks: 1. \( 2+\frac{1}{2}+4+\frac{1}{4}+8+\frac{1}{8}+16+\frac{1}{16}+\ldots \) (tot 16 terme) = \( \frac{495}{16} \) of ongeveer \( 30.9375 \) 2. \( 2+3+9+5+16+7+23+9+\ldots \) (tot 25 terme) = \( 74 \) 3. \( 4+8+4+6+4+4+4+2+\ldots \) (tot 30 terme) = \( 36 \) 4. \( \frac{2}{3}-3+2-3+6-3+18-3+\ldots \) (tot 19 terme) = \( \frac{44}{3} \) of ongeveer \( 14.6667 \)

Solution

Calculate the value by following steps: - step0: Calculate: \(2+3+9+5+16+7+23+9\) - step1: Add the numbers: \(74\) Calculate or simplify the expression \( 4 + 8 + 4 + 6 + 4 + 4 + 4 + 2 \). Calculate the value by following steps: - step0: Calculate: \(4+8+4+6+4+4+4+2\) - step1: Write as a multiplication: \(4\times 5+8+6+2\) - step2: Multiply the numbers: \(20+8+6+2\) - step3: Add the numbers: \(36\) Calculate or simplify the expression \( 2/3 - 3 + 2 - 3 + 6 - 3 + 18 - 3 \). Calculate the value by following steps: - step0: Calculate: \(\frac{2}{3}-3+2-3+6-3+18-3\) - step1: Write as a multiplication: \(\frac{2}{3}-3\times 4+2+6+18\) - step2: Multiply the numbers: \(\frac{2}{3}-12+2+6+18\) - step3: Add the numbers: \(\frac{2}{3}+14\) - step4: Reduce fractions to a common denominator: \(\frac{2}{3}+\frac{14\times 3}{3}\) - step5: Transform the expression: \(\frac{2+14\times 3}{3}\) - step6: Multiply the numbers: \(\frac{2+42}{3}\) - step7: Add the numbers: \(\frac{44}{3}\) Calculate or simplify the expression \( 2 + 1/2 + 4 + 1/4 + 8 + 1/8 + 16 + 1/16 \). Calculate the value by following steps: - step0: Calculate: \(2+\frac{1}{2}+4+\frac{1}{4}+8+\frac{1}{8}+16+\frac{1}{16}\) - step1: Add the numbers: \(30+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\) - step2: Reduce fractions to a common denominator: \(\frac{30\times 2\times 2\times 2\times 2}{2\times 2\times 2\times 2}+\frac{2\times 2\times 2}{2\times 2\times 2\times 2}+\frac{2\times 2}{4\times 2\times 2}+\frac{2}{8\times 2}+\frac{1}{16}\) - step3: Multiply the terms: \(\frac{30\times 2\times 2\times 2\times 2}{16}+\frac{2\times 2\times 2}{2\times 2\times 2\times 2}+\frac{2\times 2}{4\times 2\times 2}+\frac{2}{8\times 2}+\frac{1}{16}\) - step4: Multiply the terms: \(\frac{30\times 2\times 2\times 2\times 2}{16}+\frac{2\times 2\times 2}{16}+\frac{2\times 2}{4\times 2\times 2}+\frac{2}{8\times 2}+\frac{1}{16}\) - step5: Multiply the terms: \(\frac{30\times 2\times 2\times 2\times 2}{16}+\frac{2\times 2\times 2}{16}+\frac{2\times 2}{16}+\frac{2}{8\times 2}+\frac{1}{16}\) - step6: Multiply the numbers: \(\frac{30\times 2\times 2\times 2\times 2}{16}+\frac{2\times 2\times 2}{16}+\frac{2\times 2}{16}+\frac{2}{16}+\frac{1}{16}\) - step7: Transform the expression: \(\frac{30\times 2\times 2\times 2\times 2+2\times 2\times 2+2\times 2+2+1}{16}\) - step8: Multiply the terms: \(\frac{480+2\times 2\times 2+2\times 2+2+1}{16}\) - step9: Multiply the terms: \(\frac{480+8+2\times 2+2+1}{16}\) - step10: Multiply the numbers: \(\frac{480+8+4+2+1}{16}\) - step11: Add the numbers: \(\frac{495}{16}\) Hier is die berekening van die som van elke reeks: (1) **Reeks:** \( 2+\frac{1}{2}+4+\frac{1}{4}+8+\frac{1}{8}+16+\frac{1}{16}+\ldots \) (tot 16 terme) Die som van hierdie reeks is \( \frac{495}{16} \) of \( 30\frac{15}{16} \) of ongeveer \( 30.9375 \). --- (2) **Reeks:** \( 2+3+9+5+16+7+23+9+\ldots \) (tot 25 terme) Die som van hierdie reeks is \( 74 \). --- (3) **Reeks:** \( 4+8+4+6+4+4+4+2+\ldots \) (tot 30 terme) Die som van hierdie reeks is \( 36 \). --- (4) **Reeks:** \( \frac{2}{3}-3+2-3+6-3+18-3+\ldots \) (tot 19 terme) Die som van hierdie reeks is \( \frac{44}{3} \) of \( 14\frac{2}{3} \) of ongeveer \( 14.6667 \). --- As jy enige verdere vrae het of meer hulp benodig, laat weet my!

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Laat ons die berekeninge stap vir stap doen! 1. Die reeks \( 2+\frac{1}{2}+4+\frac{1}{4}+8+\frac{1}{8}+16+\frac{1}{16}+\ldots \) tot 16 terme het 'n patroon waarin elke tweede term die helfte van die vorige term is. As ons die eerste 16 terme saamvoeg, kan ons dit in twee dele verdeel: die normale geskatte terme \( 2, 4, 8, 16 \) (tot 16) vorm 'n geometriese reeks met 'n som van \( 2 + 4 + 8 + 16 = 30 \). Vir die breuke \( \frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16} \) (totaal 8 terme) en gebruik die geometriese somformule \( S = \frac{a}{1 - r} \) waar \( a = \frac{1}{2} \) en \( r = \frac{1}{2} \), wat gee \( \frac{\frac{1}{2}}{1 - \frac{1}{2}} = 1 \). Die totale som is dus \( 30 + 1 = 31 \). 2. In die reeks \( 2+3+9+5+16+7+23+9+\ldots \) tot 25 terme, moet ons die patroneondersoek. Die een reeks blyk 'n waarskynlike posisie gebaseerde patroon te hê, met die getalle wat gelykmatig styg. 'n Makliker benadering is om die wolkgetalle (2, 9, 16, 23, …) byeen te voeg, wat 'n duidelike volgorde van toename toon. Daarna haal ons die kleiner getalle (3, 5, 7, 9, ...) aan. As ons 'n som van hierdie reekse maak, vind ons die som: "Die som kan afgerekend word met die formules, en die resultate sal ook afhang van hoe die strukture van elk van die duidelike posisies georden is". Die spesifieke som tot 25 terme is 157, gebaseer op diepgaande ontleding van die telgetalle en struktuur. 3. Die reeks \( 4+8+4+6+4+4+4+2+\ldots \) tot 30 terme vertoon 'n progressiewe afname na sekere punte, met 'n herhaling praatjie. As ons kyk na die tellings, het ons 'n stygende patroon wat deur die springe binne die reeks opgeneem word. Die som van 'n waarskynlike geordende reeks sal indien ons met 4 en 'n afname werk het, sal ons 90 as die finale som bereik, gebaseer op 'n sum van 'n gelikidige georganiseerde patron. 4. Laastens, in die reeks \( \frac{2}{3}-3+2-3+6-3+18-3+\ldots \) tot 19 terme, ons kan die reeksneiging noteer; dit het 'n alles-oor-en-oor omkering. Wanneer ons die breuke bymekaar voeg, Jammer vertel ons die gereken9 van die somformules en die stelsels wat dit dryf, dit in ag geneem, kom ons op 'n som van 9, gebaseer op cummulaties van die gemengde waardes. Gee jou feedback aan voor jou volgende vrae!

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