Let's find \( \frac{2}{3}+\frac{1}{4} \). \( \begin{array}{l}\text { First write the addition with a common denominator, } \\ \text { Then add, } \\ \frac{2}{3}+\frac{1}{4}=\frac{\square}{\square}+\frac{\square}{\square}=\frac{\square}{\square}\end{array} \)

To add the fractions \( \frac{2}{3} \) and \( \frac{1}{4} \), we first need to find a common denominator. The least common multiple of 3 and 4 is 12. Now, we can rewrite each fraction with the common denominator: \[ \frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12} \] and \[ \frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}. \] Now we can add the two fractions: \[ \frac{2}{3}+\frac{1}{4}=\frac{8}{12}+\frac{3}{12}=\frac{8+3}{12}=\frac{11}{12}. \] So the completed addition looks like this: \[ \frac{2}{3}+\frac{1}{4}=\frac{8}{12}+\frac{3}{12}=\frac{11}{12}. \]