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If \( B=2 s+s^{2} \) and \( A=3-4 s^{2} \), find an expression that equals \( B+3 A \) in standard form. Answer Attempt 1 out of 2

Ask by Guerrero Ortiz. in the United States
Feb 26,2025

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Tutor-Verified Answer

Answer

\( B + 3A = -11s^2 + 2s + 9 \)

Solution

To find an expression that equals \( B + 3A \), we will first substitute the expressions for \( A \) and \( B \) into the equation. 1. **Identify the expressions:** - \( B = 2s + s^2 \) - \( A = 3 - 4s^2 \) 2. **Substitute \( A \) into \( B + 3A \):** \[ B + 3A = (2s + s^2) + 3(3 - 4s^2) \] 3. **Distribute \( 3 \) in the expression:** \[ B + 3A = 2s + s^2 + 9 - 12s^2 \] 4. **Combine like terms:** - Combine the \( s^2 \) terms: \( s^2 - 12s^2 = -11s^2 \) - The \( s \) term remains \( 2s \) - The constant term is \( 9 \) 5. **Write the final expression in standard form:** \[ B + 3A = -11s^2 + 2s + 9 \] Thus, the expression that equals \( B + 3A \) in standard form is: \[ \boxed{-11s^2 + 2s + 9} \]

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To find the expression for \( B + 3A \), we start by substituting \( B \) and \( A \) into the equation. Given: \[ B = 2s + s^2 \] \[ A = 3 - 4s^2 \] We can calculate \( 3A \): \[ 3A = 3(3 - 4s^2) = 9 - 12s^2 \] Now, we add \( B \) and \( 3A \): \[ B + 3A = (2s + s^2) + (9 - 12s^2) \] Combining like terms, we have: \[ B + 3A = 2s + s^2 - 12s^2 + 9 = 2s - 11s^2 + 9 \] Rearranging the terms into standard form gives us: \[ B + 3A = -11s^2 + 2s + 9 \] So, the expression that equals \( B + 3A \) in standard form is: \[ -11s^2 + 2s + 9 \]

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