Dad is 4 times as old as his son Jim. In 10 years, Dad's age will be 20 years more than twice Jim's age. How old is Jim? If \( D= \) dad's age now and \( J= \) Jim's age now, which of the following systems could be used to solve the problem? \( D=4 J \) and \( D+10=2(4 J+10)+20 \) \( D=4 J \) and \( D+10=2(J+10)+20 \) \( D=4 J \) and \( D+10=2 J+20 \)
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Mind Expander
To crack this age riddle, let's break it down. We're told that currently, Dad's age (\(D\)) is four times Jim's age (\(J\)). So, we start with the equation \(D = 4J\). Now, in 10 years, Dad's age will be \(D + 10\) and Jim's age will be \(J + 10\). The problem states that Dad's age in 10 years will be 20 years more than twice Jim's age at that time. This gives us another equation: \(D + 10 = 2(J + 10) + 20\). Based on these relationships, the correct system of equations to solve the ages is indeed \(D = 4J\) and \(D + 10 = 2(J + 10) + 20\). In your options, that’s the second one: \(D = 4J\) and \(D + 10 = 2(J + 10) + 20\). Now get out those calculators, and let's solve for Jim! If you're curious about real-world applications, age puzzles like these can help develop logical reasoning and algebraic thinking skills that are useful in everyday decision-making and planning. Whether it’s dividing responsibilities or planning birthdays, these principles pop up everywhere!