13. A salesman travelled 450 km in a day: one-third of the distance before lunch and two-fifths between lunch and tea. The rest was after tea. Write a ratio for the distance travelled before lunch: between lunch and tea: after to

Before lunch, the salesman traveled one-third of 450 km, which is 150 km. Between lunch and tea, he covered two-fifths of the total distance, equating to 180 km. Thus, the remaining distance after tea is 450 km - (150 km + 180 km) = 120 km. The ratio for the distances traveled can be expressed as 150 km: 180 km: 120 km, which simplifies to 5:6:4. To simplify this further, you can divide each part of the ratio by 30: (150 ÷ 30):(180 ÷ 30):(120 ÷ 30) = 5:6:4. This is a neat illustration of how fractions can be used to break down larger numbers into more manageable pieces, making math not only accessible but also a little more fun!