a. Rewrite the equation \( 4 x+y-3=0 \) in slope-intercept form. b. Give the slope and \( y \)-intercept. c. Use the slope and \( y \)-intercept to graph the linear function.

To rewrite the equation \( 4x + y - 3 = 0 \) in slope-intercept form, we need to solve for \( y \). Start by isolating \( y \): \[ y = -4x + 3 \] Now, it’s in the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept. The slope of the line is \( -4 \) (which means it decreases as you move from left to right), and the \( y \)-intercept is \( 3 \) (that’s the point where the line crosses the \( y \)-axis at \( (0, 3) \)). To graph the linear function, start at the \( y \)-intercept: plot the point \( (0, 3) \) on the \( y \)-axis. From there, use the slope \( -4 \), which means that for every 1 unit you move to the right (positive direction on the \( x \)-axis), move down 4 units. Plot another point at \( (1, -1) \). Connect the points with a straight line, and you’ve successfully graphed the linear function!