Solve the system of equations by any method. \[ \begin{array}{r}-2 x+5 y=-21 \\ 7 x+2 y=15\end{array} \] Enter the exact answer as an ordered pair, ( \( x, y \) ). If there is no solution, enter NS. If there is an infinite number of solutions, enter the general solut an ordered pair in terms of \( x \). Include a multiplication sign between symbols. For example, \( a * x \). I ?
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To solve the system of equations \[ \begin{array}{r} -2x + 5y = -21 \\ 7x + 2y = 15 \end{array} \] we can use the substitution or elimination method. Let's use elimination here. First, let's multiply the first equation by 7 to eliminate \( x \): \[ -14x + 35y = -147 \quad (1) \] Now, we multiply the second equation by 2: \[ 14x + 4y = 30 \quad (2) \] Now, we can add equations (1) and (2): \[ (-14x + 35y) + (14x + 4y) = -147 + 30 \] \[ 39y = -117 \] \[ y = -3 \] Now that we have \( y \), we can substitute it back into one of the original equations to find \( x \). Using the first equation: \[ -2x + 5(-3) = -21 \] \[ -2x - 15 = -21 \] \[ -2x = -6 \] \[ x = 3 \] Thus, the solution to the system of equations is the ordered pair \( (3, -3) \).