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Solve the inequality \( 3(x+2)>0 \) \( x<2 \) \( x>2 \) \( x<-2 \) \( x>-2 \)

Ask by Colon Hampton. in the United States
Feb 25,2025

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Answer

\( x > -2 \)

Solution

We start with the inequality:   3(x + 2) > 0. Since 3 is positive, we can divide both sides by 3 without changing the inequality sign:   x + 2 > 0. Subtract 2 from both sides:   x > -2. Thus, the correct answer is: x > -2.

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To solve the inequality \( 3(x+2) > 0 \), first, divide both sides by 3 (since 3 is positive, the inequality doesn't change direction). This gives us \( x + 2 > 0 \). Next, subtract 2 from both sides to isolate \( x \): \[ x > -2 \] So the solution to the inequality is \( x > -2 \). Now, you can choose the correct option based on this solution, which is \( x > -2 \).

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