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answer in terma of \( y \) QUENTION 2 The firat three forms of an ariflimetio sequence are 4; 13 and 22 1 Write down the fourth term of this sequence. 2 Determine the general torm of the sequence, 3 Consider the torms of this sequence which are even, Calculate tho sum of tho first 25 terms which are even.

Ask by Chang Cole. in South Africa
Feb 25,2025

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1. The fourth term is 31. 2. The general term is \( a_n = 9n - 5 \). 3. The sum of the first 25 even terms is 5500.

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To find the fourth term of the arithmetic sequence, first determine the common difference by subtracting the first term from the second: \( 13 - 4 = 9 \). The fourth term can then be calculated as \( 22 + 9 = 31 \). Next, the general term of an arithmetic sequence is given by the formula \( a_n = a_1 + (n-1)d \). Here, \( a_1 = 4 \) and \( d = 9 \). Therefore, the general term is \( a_n = 4 + (n-1) \cdot 9 = 9n - 5 \). Now, for the even terms, we need to find when \( 9n - 5 \) is even. This occurs when \( n \) is odd (as \( 9n \) will be odd when \( n \) is odd and subtracting 5 will yield an even number). The odd terms are \( n = 1, 3, 5, \ldots \). The first 25 odd integers are \( 1, 3, 5, \ldots, 49 \). The corresponding even terms are \( a_1, a_3, a_5, \ldots, a_{49} \), which form another arithmetic sequence with first term \( a_1 = 4 \) and common difference \( d = 18 \) (every alternate term increases by 18). The sum of the first 25 even terms can be calculated with the formula for the sum of an arithmetic series: \[ S_{25} = \frac{n}{2} \cdot (2a + (n-1)d) \] Substituting \( n = 25 \), \( a = 4 \), and \( d = 18 \): \[ S_{25} = \frac{25}{2} \cdot (2 \cdot 4 + (25-1) \cdot 18) \\ = \frac{25}{2} \cdot (8 + 24 \cdot 18) \\ = \frac{25}{2} \cdot (8 + 432) \\ = \frac{25}{2} \cdot 440 \\ = 25 \cdot 220 = 5500 \] Thus, the sum of the first 25 even terms is \( 5500 \).

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