The first period of the graph of $$ y=\sin (x) $$ starts at $$ y= $$ a $$ \pi $$ b 1 c 0 d $$ \frac{\pi}{2} $$ e -1

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To determine where the first period of the graph of $$ y = \sin(x) $$ starts, we need to analyze the sine function.

1. The sine function, $$ y = \sin(x) $$, has a range of values from -1 to 1.
2. The function starts at $$ y = 0 $$ when $$ x = 0 $$.
3. The first period of the sine function is from $$ x = 0 $$ to $$ x = 2\pi $$.

Given these points, the starting value of the sine function at the beginning of its first period (when $$ x = 0 $$) is:

$$
y = \sin(0) = 0
$$

Thus, the correct answer is:

c) 0
The first period of the graph of $$ y = \sin(x) $$ starts at $$ y = 0 $$.

The first period of the graph of \( y=\sin (x) \) starts at \( y= \) a \( \pi \) b 1 c 0 d \( \frac{\pi}{2} \) e -1

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