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Question 1 1 Simplify the following surds: \( 1.1 \quad \sqrt{75} \) \( 1.2 \quad \sqrt{50}+\sqrt{18} \) \( 1.3 \quad \frac{\sqrt{48}}{\sqrt{3}} \) \( 1.4 \quad \sqrt{27}+\sqrt{12} \) Question 2 2 Perform the following operations with surds \( 2.1 \quad \sqrt{18}+\sqrt{32} \) \( 2.2 \quad \sqrt{75}-\sqrt{12} \) \( 2.3 \quad \sqrt{6} \times \sqrt{3} \) \( 2.4 \quad \sqrt{8} \times \sqrt{2} \) \( 2.5 \quad \sqrt{18}+\sqrt{8} \) \( 2.6 \quad \sqrt{20}+\sqrt{45}-\sqrt{80} \) Question 3 3 Rationalize the denominator of the following expressions: \( 3.1 \quad \frac{5}{\sqrt{3}} \)

Ask by Weston Alexander. in South Africa
Feb 27,2025

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- **Question 1:** - 1.1 \( 5\sqrt{3} \) - 1.2 \( 8\sqrt{2} \) - 1.3 \( 4 \) - 1.4 \( 5\sqrt{3} \) - **Question 2:** - 2.1 \( 7\sqrt{2} \) - 2.2 \( 3\sqrt{3} \) - 2.3 \( 3\sqrt{2} \) - 2.4 \( 4 \) - 2.5 \( 5\sqrt{2} \) - 2.6 \( \sqrt{5} \) - **Question 3:** - 3.1 \( \frac{5\sqrt{3}}{3} \)

Solution

Calculate the value by following steps: - step0: Calculate: \(50+18\) - step1: Add the numbers: \(68\) Calculate or simplify the expression \( 18+32 \). Calculate the value by following steps: - step0: Calculate: \(18+32\) - step1: Add the numbers: \(50\) Calculate or simplify the expression \( 5/\sqrt(3) \). Calculate the value by following steps: - step0: Calculate: \(\frac{5}{\sqrt{3}}\) - step1: Multiply by the Conjugate: \(\frac{5\sqrt{3}}{\sqrt{3}\times \sqrt{3}}\) - step2: Multiply the numbers: \(\frac{5\sqrt{3}}{3}\) Calculate or simplify the expression \( 48/3 \). Calculate the value by following steps: - step0: Calculate: \(\frac{48}{3}\) - step1: Reduce the numbers: \(\frac{16}{1}\) - step2: Calculate: \(16\) Calculate or simplify the expression \( 75 \). Numbers by following steps: - step0: Solution: \(75\) Calculate or simplify the expression \( 8*2 \). Calculate the value by following steps: - step0: Calculate: \(8\times 2\) - step1: Multiply the numbers: \(16\) Calculate or simplify the expression \( 75-12 \). Calculate the value by following steps: - step0: Calculate: \(75-12\) - step1: Subtract the numbers: \(63\) Calculate or simplify the expression \( 6*3 \). Calculate the value by following steps: - step0: Calculate: \(6\times 3\) - step1: Multiply the numbers: \(18\) Calculate or simplify the expression \( 27+12 \). Calculate the value by following steps: - step0: Calculate: \(27+12\) - step1: Add the numbers: \(39\) Calculate or simplify the expression \( 18+8 \). Calculate the value by following steps: - step0: Calculate: \(18+8\) - step1: Add the numbers: \(26\) Calculate or simplify the expression \( 20+45-80 \). Calculate the value by following steps: - step0: Calculate: \(20+45-80\) - step1: Calculate: \(-15\) Let's solve the problems step by step. ### Question 1: Simplify the following surds 1.1 \( \sqrt{75} \) To simplify \( \sqrt{75} \): \[ \sqrt{75} = \sqrt{25 \times 3} = \sqrt{25} \times \sqrt{3} = 5\sqrt{3} \] 1.2 \( \sqrt{50} + \sqrt{18} \) To simplify \( \sqrt{50} \) and \( \sqrt{18} \): \[ \sqrt{50} = \sqrt{25 \times 2} = 5\sqrt{2} \] \[ \sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2} \] Now combine: \[ \sqrt{50} + \sqrt{18} = 5\sqrt{2} + 3\sqrt{2} = 8\sqrt{2} \] 1.3 \( \frac{\sqrt{48}}{\sqrt{3}} \) To simplify \( \frac{\sqrt{48}}{\sqrt{3}} \): \[ \frac{\sqrt{48}}{\sqrt{3}} = \sqrt{\frac{48}{3}} = \sqrt{16} = 4 \] 1.4 \( \sqrt{27} + \sqrt{12} \) To simplify \( \sqrt{27} \) and \( \sqrt{12} \): \[ \sqrt{27} = \sqrt{9 \times 3} = 3\sqrt{3} \] \[ \sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3} \] Now combine: \[ \sqrt{27} + \sqrt{12} = 3\sqrt{3} + 2\sqrt{3} = 5\sqrt{3} \] ### Question 2: Perform the following operations with surds 2.1 \( \sqrt{18} + \sqrt{32} \) To simplify: \[ \sqrt{18} = 3\sqrt{2}, \quad \sqrt{32} = 4\sqrt{2} \] Combine: \[ \sqrt{18} + \sqrt{32} = 3\sqrt{2} + 4\sqrt{2} = 7\sqrt{2} \] 2.2 \( \sqrt{75} - \sqrt{12} \) To simplify: \[ \sqrt{75} = 5\sqrt{3}, \quad \sqrt{12} = 2\sqrt{3} \] Combine: \[ \sqrt{75} - \sqrt{12} = 5\sqrt{3} - 2\sqrt{3} = 3\sqrt{3} \] 2.3 \( \sqrt{6} \times \sqrt{3} \) To simplify: \[ \sqrt{6} \times \sqrt{3} = \sqrt{18} = 3\sqrt{2} \] 2.4 \( \sqrt{8} \times \sqrt{2} \) To simplify: \[ \sqrt{8} \times \sqrt{2} = \sqrt{16} = 4 \] 2.5 \( \sqrt{18} + \sqrt{8} \) To simplify: \[ \sqrt{18} = 3\sqrt{2}, \quad \sqrt{8} = 2\sqrt{2} \] Combine: \[ \sqrt{18} + \sqrt{8} = 3\sqrt{2} + 2\sqrt{2} = 5\sqrt{2} \] 2.6 \( \sqrt{20} + \sqrt{45} - \sqrt{80} \) To simplify: \[ \sqrt{20} = 2\sqrt{5}, \quad \sqrt{45} = 3\sqrt{5}, \quad \sqrt{80} = 4\sqrt{5} \] Combine: \[ \sqrt{20} + \sqrt{45} - \sqrt{80} = 2\sqrt{5} + 3\sqrt{5} - 4\sqrt{5} = 1\sqrt{5} = \sqrt{5} \] ### Question 3: Rationalize the denominator of the following expressions 3.1 \( \frac{5}{\sqrt{3}} \) To rationalize: \[ \frac{5}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{5\sqrt{3}}{3} \] ### Summary of Results - **Question 1:** - 1.1 \( 5\sqrt{3} \) - 1.2 \( 8\sqrt{2} \) - 1.3 \( 4 \) - 1.4 \( 5\sqrt{3} \) - **Question 2:** - 2.1 \( 7\sqrt{2} \) - 2.2 \( 3\sqrt{3} \) - 2.3 \( 3\sqrt{2} \) - 2.4 \( 4 \) - 2.5 \( 5\sqrt{2} \) - 2.6 \( \sqrt{5} \) - **Question 3:** - 3.1 \( \frac{5\sqrt{3}}{3} \)

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To simplify \( \sqrt{75} \), we notice that \( 75 = 25 \times 3 \). Thus, \( \sqrt{75} = \sqrt{25 \times 3} = \sqrt{25} \times \sqrt{3} = 5\sqrt{3} \). Similarly, \( \sqrt{50}+\sqrt{18} \) simplifies to \( 5\sqrt{2} + 3\sqrt{2} = 8\sqrt{2} \) after breaking them down into \( 25 \times 2 \) and \( 9 \times 2 \) respectively. Rationalizing \( \frac{5}{\sqrt{3}} \) involves multiplying both the numerator and denominator by \( \sqrt{3} \). This gives \( \frac{5\sqrt{3}}{3} \). This process makes the denominator a rational number, which is often preferred in mathematics for clarity and simplicity in further calculations. In the magical world of math, surds are like hidden gems waiting to be uncovered! Simplifying them allows you to find their true beauty, revealing simpler roots or clean expressions. Embrace the adventure of numbers, where each simplification is a treasure hunt leading to clarity in calculations. To dive deeper, consider exploring how surds are used in geometry, particularly in finding lengths of sides in right triangles using the Pythagorean theorem. Alternatively, biographies of mathematicians like Euclid or modern figures who tackled irrational numbers provide exciting contexts to these tricky elements of math!

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