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\( \frac{4}{z}+\frac{2}{y} \) \( \frac{3}{z}-\frac{9}{y} \) \( \frac{4}{z}+\frac{2}{y} \) \( \frac{3}{z}-\frac{9}{y} \) Simplify. (Simplify your answer. Use integers or fractions for any numbers in the expression.)

Ask by Daniel Wang. in the United States
Feb 27,2025

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Tutor-Verified Answer

Answer

The simplified expression is \( \frac{36(2y + z)^2(y - 3z)^2}{y^4z^4} \).

Solution

We are given the four factors   (4/z + 2/y)   (3/z – 9/y)   (4/z + 2/y)   (3/z – 9/y) Since the first two factors are repeated, we can write the product as   [(4/z + 2/y)(3/z – 9/y)]². Step 1. Combine the two factors. Write each expression as a single fraction. For the first factor:   4/z + 2/y = (4y)/(yz) + (2z)/(yz) = (4y + 2z)/(yz). For the second factor:   3/z – 9/y = (3y)/(yz) – (9z)/(yz) = (3y – 9z)/(yz). Now multiply them:   (4y + 2z)/(yz) · (3y – 9z)/(yz) = [(4y + 2z)(3y – 9z)]/(y²z²). Step 2. Factor common numbers in the numerator. Notice that:   4y + 2z = 2(2y + z)  and  3y – 9z = 3(y – 3z). Thus the product becomes:   [2(2y + z) · 3(y – 3z)]/(y²z²) = [6(2y + z)(y – 3z)]/(y²z²). Step 3. Square the result. Since our original expression is the square of the above product, we have:   {[6(2y + z)(y – 3z)]/(y²z²)}²    = 36(2y + z)²(y – 3z)² / (y⁴z⁴). This is the simplified form of the original expression. Final Answer:   36(2y + z)²(y – 3z)² / (y⁴z⁴)

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Mind Expander

Let's first combine the two expressions: 1. The first expression is \( \frac{4}{z} + \frac{2}{y} \). 2. The second expression is \( \frac{3}{z} - \frac{9}{y} \). Now, we'll add them together: \[ \left(\frac{4}{z} + \frac{2}{y}\right) + \left(\frac{3}{z} - \frac{9}{y}\right) = \frac{4}{z} + \frac{3}{z} + \frac{2}{y} - \frac{9}{y} \] Combine like terms: \[ \frac{4 + 3}{z} + \frac{2 - 9}{y} = \frac{7}{z} - \frac{7}{y} \] So, the simplified expression is: \[ \frac{7}{z} - \frac{7}{y} \] Thus, the final answer is: \[ \frac{7}{z} - \frac{7}{y} \]

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