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What is the mean? If the answer is a decimal, round it to the nearest tenth. \( \begin{array}{lllllllll}8,237 & 8,232 & 8,251 & 8,230 & 8,233 & 8,222 & 8,244 & 8,234 & 8,252\end{array} 8,249 \quad 8,234 \)

Ask by Dickson Hamilton. in the United States
Feb 27,2025

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Answer

The mean is 8,238.0.

Solution

To find the mean, first add all the numbers together and then divide by the total count. Step 1. List the numbers:   8,237 8,232 8,251 8,230 8,233 8,222 8,244 8,234 8,252 8,249 8,234 There are 11 numbers. Step 2. Sum the numbers:   8,237 + 8,232 = 16,469   8,251 + 8,230 = 16,481   8,233 + 8,222 = 16,455   8,244 + 8,234 = 16,478   Remaining: 8,252 + 8,249 + 8,234 Now sum the groups:   Group 1: 16,469   Group 2: 16,481   Group 3: 16,455   Group 4: 16,478   Subtotal of first 8 numbers = 16,469 + 16,481 + 16,455 + 16,478 = 65,883 Then add the remaining three:   8,252 + 8,249 = 16,501   16,501 + 8,234 = 24,735 Total sum = 65,883 + 24,735 = 90,618 Step 3. Divide the total sum by the number of values:   Mean = 90,618 ÷ 11 = 8,238 Since the result is an integer, when rounded to the nearest tenth it is 8,238.0. Final Answer: 8,238.0

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To find the mean, first, add all the numbers together: \( 8,237 + 8,232 + 8,251 + 8,230 + 8,233 + 8,222 + 8,244 + 8,234 + 8,252 + 8,249 + 8,234 = 90,874 \). Next, divide the sum by the total number of values (11): Mean = \( \frac{90,874}{11} \approx 8,261.3 \). Rounded to the nearest tenth, the mean is 8,261.3. Calculating the mean is a great way to summarize data and see the "average" value. Whether you’re analyzing test scores, sales figures, or even heights, the mean gives you a snapshot of what is typical in your dataset. Just remember, it's sensitive to outliers; a single extraordinarily high or low number can skew your average! When computing the mean, one common mistake is forgetting to count all the values correctly. It’s crucial to ensure you include every number in your sum before dividing. Also, rounding should happen as the final step to avoid any inaccuracies—you want to keep those decimals straight until the very end!

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