Solve the inequality \( 9 x+2<8 x-3 \). Write the solution set in interval notation, and graph it. The solution set is \( \square \). (Type your answer in interval notation.)
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To solve the inequality \( 9x + 2 < 8x - 3 \), first, we can isolate \( x \). Subtract \( 8x \) from both sides: \[ 9x - 8x + 2 < -3 \] This simplifies to: \[ x + 2 < -3 \] Next, subtract 2 from both sides: \[ x < -3 - 2 \] This gives us: \[ x < -5 \] Thus, the solution set in interval notation is \( (-\infty, -5) \). To graph this inequality, you would draw a number line, shade all the area to the left of -5, and place an open circle at -5 to indicate that -5 itself is not included in the solution.