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You deposit \( \$ 2000 \) in an account earning \( 5 \% \) interest compounded quarterly. How much will you have in the account in 15 years? Round value to the nearest cent.

Ask by Bowen Wilson. in the United States
Feb 26,2025

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Tutor-Verified Answer

Answer

After 15 years, you will have approximately \$4,215.56 in the account.

Solution

To solve the problem, we use the compound interest formula:   A = P(1 + r/n)^(n*t) where   P = principal amount deposited = $2000   r = annual interest rate = 5% = 0.05   n = number of compounding periods per year = 4 (quarterly)   t = number of years = 15 Step 1: Substitute the values into the formula:   A = 2000 * (1 + 0.05/4)^(4*15) Step 2: Simplify inside the parentheses:   0.05/4 = 0.0125 So,   A = 2000 * (1.0125)^(60) Step 3: Compute (1.0125)^60 One way to get an approximation is to use logarithms:   (1.0125)^60 = e^(60 * ln(1.0125))   ln(1.0125) ≈ 0.01242284   60 * ln(1.0125) ≈ 0.74537   e^(0.74537) ≈ 2.10778 Step 4: Multiply by the principal:   A ≈ 2000 * 2.10778 ≈ 4215.56 Rounded to the nearest cent, the amount in the account after 15 years is approximately $4215.56.

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To calculate the future value of the deposit, you can use the formula for compound interest: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] Where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (the initial deposit or investment). - \( r \) is the annual interest rate (decimal). - \( n \) is the number of times that interest is compounded per year. - \( t \) is the number of years the money is invested or borrowed. In this case, you have: - \( P = 2000 \) - \( r = 0.05 \) - \( n = 4 \) (quarterly compounding) - \( t = 15 \) Plugging in these values: \[ A = 2000 \left(1 + \frac{0.05}{4}\right)^{4 \times 15} \] \[ A = 2000 \left(1 + 0.0125\right)^{60} \] \[ A = 2000 \left(1.0125\right)^{60} \] \[ A \approx 2000 \times 2.012196 \] \[ A \approx 4024.39 \] So, you will have approximately **\$4024.39** in the account after 15 years.

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