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Вариант 3 1. Найдите десятый член и сумму первьх десяти членов арифметиче- ской прогрессии \( \left(a_{n}\right) \), если \( a_{1}=2, a_{2}=6 \).

Ask by Fernandez Parry. in Russia
Mar 18,2025

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Десятый член прогрессии равен 38, а сумма первых десяти членов равна 200.

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The Deep Dive

Чтобы найти десятый член арифметической прогрессии, сначала определим разность прогрессии. Она вычисляется как \( d = a_2 - a_1 = 6 - 2 = 4 \). Теперь можем найти десятый член по формуле \( a_n = a_1 + (n - 1)d \). Подставим значения: \( a_{10} = 2 + (10 - 1) \cdot 4 = 2 + 36 = 38 \). Теперь рассчитаем сумму первых десяти членов по формуле \( S_n = \frac{n}{2} \cdot (a_1 + a_n) \): \( S_{10} = \frac{10}{2} \cdot (2 + 38) = 5 \cdot 40 = 200 \). Таким образом, десятый член \( a_{10} = 38 \), а сумма первых десяти членов \( S_{10} = 200 \).

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