Answer the questions below. (a) The perimeter of a rectangular field is 336 m . If the length of the field is 89 m , what is its width? Width of the field: \( \square \mathrm{m} \) (b) The area of a rectangular painting is \( 4617 \mathrm{~cm}^{2} \). If the width of the painting is 57 cm , what is its length? Length of the painting: \( \square \mathrm{cm} \)

To find the width of the rectangular field, we can use the perimeter formula \( P = 2(l + w) \), where \( l \) is the length and \( w \) is the width. Given that the perimeter is 336 m and the length is 89 m: \[ 336 = 2(89 + w) \] \[ 168 = 89 + w \] \[ w = 168 - 89 = 79 \text{ m} \] So, the width of the field is \( 79 \mathrm{~m} \). For the painting, the area formula is \( A = l \times w \). Given that the area is \( 4617 \mathrm{~cm}^2 \) and the width is 57 cm: \[ 4617 = l \times 57 \] \[ l = \frac{4617}{57} = 81 \text{ cm} \] Therefore, the length of the painting is \( 81 \mathrm{~cm} \). Width of the field: \( 79 \mathrm{m} \) Length of the painting: \( 81 \mathrm{cm} \)