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Question 1 (1 point) What is the rate of growth or rate of decay? \[ y=5575(0.65)^{x} \] a \( x \) b 5575 c \( \quad .65 \) d 1

Ask by Vargas Weston. in the United States
Feb 26,2025

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The rate of decay is 0.65.

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To determine the rate of growth or decay from the given equation \( y = 5575(0.65)^{x} \), we need to analyze the base of the exponential function. 1. **Identify the components of the equation:** - The equation is in the form \( y = a(b)^{x} \), where: - \( a = 5575 \) (the initial value) - \( b = 0.65 \) (the base of the exponential function) 2. **Determine the nature of the base \( b \):** - If \( b < 1 \), the function represents exponential decay. - If \( b > 1 \), the function represents exponential growth. In this case, since \( b = 0.65 \), which is less than 1, the function represents exponential decay. 3. **Calculate the rate of decay:** - The rate of decay can be found using the formula \( r = 1 - b \). - Here, \( r = 1 - 0.65 = 0.35 \). Thus, the rate of decay is 0.35, which indicates that the function decreases by 35% for each unit increase in \( x \). **Final Answer:** The correct option that represents the rate of decay is: - c \( 0.65 \) (indicating the decay factor, but the rate of decay itself is \( 0.35 \)). However, if we are strictly looking for the decay factor, the answer is \( 0.65 \).

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The equation you provided, \( y = 5575(0.65)^{x} \), exhibits decay rather than growth because the base is less than 1. Specifically, the 0.65 means that for each unit increase in \( x \), the value of \( y \) is multiplied by 0.65, indicating a reduction over time. This is a common feature in exponential decay models, such as those used to track radioactive decay or depreciation of assets. In this context, the rate of decay can be extracted from the base of the exponential. The specific decay rate of 0.65 indicates a 35% decrease (which is 1 - 0.65) in the value for every increase of 1 in \( x \). This rate is pivotal when modeling systems that lose value over time, such as a car depreciating on the lot!

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