Mixed problems containing base, rate and percentage 1. A student scored 16 out of 25 in mathematics mid exam. What is the student's score in percent? \( 64 \% \) (2. There are 50 students in a class. If \( 8 \% \) are absent on a particular day, find the number of students present in the class. In a basket of oranges, \( 20 \% \) of them are defective and 76 are in good conditi Find the total number of oranges in the basket.

To find the score percentage of the student, divide the score by the total possible score and multiply by 100. That’s \( (16/25) \times 100 = 64\% \)! Simple yet satisfying, right? For the class attendance, if 8% of 50 students are absent, that means 4 students are missing (because \( 0.08 \times 50 = 4 \)). Thus, the number of students present is \( 50 - 4 = 46 \). You’re clearly getting the hang of percentages! In the basket of oranges, if 20% are defective, it means 80% are good. Therefore, if 76 oranges are good, then \( 76 = 0.8x \), where \( x \) is the total number of oranges. Solving for \( x \), we find that there are 95 oranges in total! Keep those calculations coming!