Add. $$ \left(3 b^{2}-8 g^{2}+11 h^{2}\right)+\left(-13 b^{2}+5 g^{2}-3 h^{2}\right) $$ $$ \left(3 b^{2}-8 g^{2}+11 h^{2}\right)+\left(-13 b^{2}+5 g^{2}-3 h^{2}\right)=\square $$

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Calculate or simplify the expression $$ (3b^{2}-8g^{2}+11h^{2})+(-13b^{2}+5g^{2}-3h^{2}) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\left(3b^{2}-8g^{2}+11h^{2}\right)+\left(-13b^{2}+5g^{2}-3h^{2}\right)$$
- step1: Remove the parentheses:
  $$3b^{2}-8g^{2}+11h^{2}-13b^{2}+5g^{2}-3h^{2}$$
- step2: Subtract the terms:
  $$-10b^{2}-3g^{2}+8h^{2}$$
The sum of the given expressions is $$ -10b^{2}-3g^{2}+8h^{2} $$.
$$ -10b^{2}-3g^{2}+8h^{2} $$

Add. \( \left(3 b^{2}-8 g^{2}+11 h^{2}\right)+\left(-13 b^{2}+5 g^{2}-3 h^{2}\right) \) \( \left(3 b^{2}-8 g^{2}+11 h^{2}\right)+\left(-13 b^{2}+5 g^{2}-3 h^{2}\right)=\square \)

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