Question
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\( \$ 8,000 \) is invested in two different accounts earning \( 3 \% \) and \( 4 \% \) interest. If the two accounts earn a total of \( \$ 295 \) in interest, how much money was invested at \( 3 \% \) ? \( \$ 3,500 \) \( \$ 5,500 \) \( \$ 2,500 \)

Ask by Turnbull Powers. in the United States
Feb 27,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

$2,500 was invested at 3%.

Solution

Let x be the amount invested at 3%. Then (8000 - x) is invested at 4%. The total interest is given by:   0.03x + 0.04(8000 - x) = 295 Simplify and solve:   0.03x + 320 - 0.04x = 295   -0.01x + 320 = 295   -0.01x = 295 - 320   -0.01x = -25   x = (-25) / (-0.01)   x = 2500 Thus, $2,500 was invested at 3%.

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Bonus Knowledge

Let's break down how to solve this problem step by step! We can set up equations based on the amounts invested in each account. Let \( x \) be the amount invested at \( 3\% \) and \( 8000 - x \) be the amount invested at \( 4\% \). The interest earned from these accounts can be expressed as: \[ 0.03x + 0.04(8000 - x) = 295 \] Now, solving for \( x \), you’ll find the amount invested at \( 3\% \)! After you expand and combine like terms, you should be able to isolate \( x \). Keep calculating until you find that the amount invested at \( 3\% \) is indeed \( \$ 3,500 \). Another fun fact: this type of problem is a classic example of linear equations applied to real-world financial scenarios! Knowing how to allocate funds efficiently is a valuable skill, especially when trying to maximize returns on investments. Always remember to balance your risk versus rewards when choosing where to invest!

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