1. Circle the equations that are true when \( \mathrm{x}=4 \) \( \begin{array}{ll}x-4=10 & 3 x=12 \\ x^{3}=12 & \frac{1}{3} x=12 \\ x^{2}=16\end{array} \)

When \( x = 4 \), let’s evaluate each equation one by one: 1. \( x - 4 = 10 \) becomes \( 4 - 4 = 10 \) → This is false because \( 0 \neq 10 \). 2. \( 3x = 12 \) becomes \( 3 \cdot 4 = 12 \) → This is true as \( 12 = 12 \). 3. \( x^3 = 12 \) becomes \( 4^3 = 12 \) → This is false because \( 64 \neq 12 \). 4. \( \frac{1}{3}x = 12 \) becomes \( \frac{1}{3} \cdot 4 = 12 \) → This is false as \( \frac{4}{3} \neq 12 \). 5. \( x^{2} = 16 \) becomes \( 4^2 = 16 \) → This is true as \( 16 = 16 \). Thus, the true equations when \( x = 4 \) are \( 3x = 12 \) and \( x^{2} = 16 \).