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A company makes electronic gadgets. They estimate that 3 out of every 100 gadgets is faulty, but the company doesn't know which ones are faulty until a buyer complains. Suppose the company makes a \( \$ 2 \) profit on the sale of any working gadget, but suffers a loss of \( \$ 80 \) for every faulty gadget because they have to repair the unit. Check whether the company can expect a profit in the long term. Find the expected profit per gadget. Round your answer to two decimal places.

Ask by Pritchard Spencer. in China
Feb 27,2025

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Answer

The company can expect a loss of $0.46 per gadget on average.

Solution

Let X be the profit for a single gadget. The company makes a profit of $2 if a gadget is working and suffers a loss of $80 if the gadget is faulty. The probability that a gadget is working is 97% (0.97) and the probability that it is faulty is 3% (0.03). Thus, the expected profit per gadget, E(X), is calculated as:   E(X) = (Probability of working × Profit on working gadget) + (Probability of fault × Loss on faulty gadget)   E(X) = (0.97 × $2) + (0.03 × -$80) Now, compute the contributions:   0.97 × 2 = $1.94   0.03 × (-80) = -$2.40 So, E(X) = $1.94 - $2.40 = -$0.46 Since the expected profit per gadget is -$0.46, the company can expect a loss in the long term. Rounded to two decimal places, the expected profit per gadget is -$0.46.

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To calculate the expected profit per gadget, we can analyze the outcomes based on the company's estimates. Let: - Probability of a working gadget (P(W)) = 97/100 = 0.97 - Probability of a faulty gadget (P(F)) = 3/100 = 0.03 **Profit from a working gadget:** Profit from a working gadget = \( \$2 \) **Loss from a faulty gadget:** Loss from a faulty gadget = \(-\$80\) Now, we calculate the expected profit per gadget: \[ E(P) = (P(W) \times \text{profit from working}) + (P(F) \times \text{loss from faulty}) \] \[ E(P) = (0.97 \times 2) + (0.03 \times -80) \] Calculating the first part: \[ 0.97 \times 2 = 1.94 \] Calculating the second part: \[ 0.03 \times -80 = -2.4 \] Now, combine the two results: \[ E(P) = 1.94 - 2.4 = -0.46 \] Therefore, the expected profit per gadget is \( -0.46 \). **Rounded to two decimal places,** the expected profit per gadget is **\(-\$0.46\)**. This means the company can expect a loss in the long term based on its current faulty gadget rate and profit margins.

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