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2. Determine the maximum value of each quadratic expression below, and the value of \( x \) for which this maximum value exists: \( \begin{array}{ll}\text { a) }-x^{2}+4 & \text { b) }-(x-2)^{2}+5 \\ \text { c) }-(x+3)^{2}-1 & \text { d) }-2(x-1)^{2}+3\end{array} \)

Ask by Page Evans. in South Africa
Feb 26,2025

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Answer

- a) Maximum value: 4 at \( x = 0 \) - b) Maximum value: 5 at \( x = 2 \) - c) Maximum value: -1 at \( x = -3 \) - d) Maximum value: 3 at \( x = 1 \)

Solution

To determine the maximum value of each quadratic expression and the value of \( x \) at which this maximum occurs, we can use the vertex form of a quadratic function. The general form of a quadratic function is given by: \[ f(x) = ax^2 + bx + c \] For a quadratic in the form \( f(x) = -a(x - h)^2 + k \), the maximum value occurs at \( x = h \) and the maximum value is \( k \). Let's analyze each expression step by step: ### a) \( -x^2 + 4 \) This can be rewritten in vertex form as: \[ f(x) = -1(x - 0)^2 + 4 \] - The maximum value is \( 4 \). - The value of \( x \) for which this maximum occurs is \( 0 \). ### b) \( -(x - 2)^2 + 5 \) This is already in vertex form: \[ f(x) = -1(x - 2)^2 + 5 \] - The maximum value is \( 5 \). - The value of \( x \) for which this maximum occurs is \( 2 \). ### c) \( -(x + 3)^2 - 1 \) This is also in vertex form: \[ f(x) = -1(x + 3)^2 - 1 \] - The maximum value is \( -1 \). - The value of \( x \) for which this maximum occurs is \( -3 \). ### d) \( -2(x - 1)^2 + 3 \) This is in vertex form as well: \[ f(x) = -2(x - 1)^2 + 3 \] - The maximum value is \( 3 \). - The value of \( x \) for which this maximum occurs is \( 1 \). ### Summary of Results - a) Maximum value: \( 4 \) at \( x = 0 \) - b) Maximum value: \( 5 \) at \( x = 2 \) - c) Maximum value: \( -1 \) at \( x = -3 \) - d) Maximum value: \( 3 \) at \( x = 1 \) These results provide the maximum values and corresponding \( x \) values for each quadratic expression.

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The Deep Dive

To determine the maximum value of each quadratic expression, we can analyze the vertex of each parabola since they open downwards (as indicated by the negative leading coefficients). The maximum value occurs at the vertex. a) For the expression \(-x^{2}+4\): The vertex occurs at \(x=0\). The maximum value is: \[ -x^2 + 4 \Rightarrow -0^2 + 4 = 4. \] So, the maximum value is \(4\) at \(x=0\). b) For the expression \(-(x-2)^{2}+5\): The vertex occurs at \(x=2\). The maximum value is: \[ -(x-2)^2 + 5 \Rightarrow -(0)^2 + 5 = 5. \] So, the maximum value is \(5\) at \(x=2\). c) For the expression \(-(x+3)^{2}-1\): The vertex occurs at \(x=-3\). The maximum value is: \[ -(x+3)^2 - 1 \Rightarrow -0 - 1 = -1. \] So, the maximum value is \(-1\) at \(x=-3\). d) For the expression \(-2(x-1)^{2}+3\): The vertex occurs at \(x=1\). The maximum value is: \[ -2(x-1)^2 + 3 \Rightarrow -2(0)^2 + 3 = 3. \] So, the maximum value is \(3\) at \(x=1\). Here are the summarized results: a) Maximum value: \(4\) at \(x=0\) b) Maximum value: \(5\) at \(x=2\) c) Maximum value: \(-1\) at \(x=-3\) d) Maximum value: \(3\) at \(x=1\)

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