Question
Question 18
Find all real solutions of the equation by completing the square \( x^{2}-12 x+30=30 \)
\( x_{1}=\square \) and \( x_{2}=\square \) with \( x_{1}
Ask by Reese Coles. in the United States
Feb 27,2025
Ask by Reese Coles. in the United States
Feb 27,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
\( x_{1}=0 \) and \( x_{2}=12 \)
Solution
Solve the equation \( x^{2}-12x+30=30 \).
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
\(x^{2}-12x+30=30\)
- step1: Move the expression to the left side:
\(x^{2}-12x=0\)
- step2: Factor the expression:
\(x\left(x-12\right)=0\)
- step3: Separate into possible cases:
\(\begin{align}&x-12=0\\&x=0\end{align}\)
- step4: Solve the equation:
\(\begin{align}&x=12\\&x=0\end{align}\)
- step5: Rewrite:
\(x_{1}=0,x_{2}=12\)
The real solutions of the equation \(x^{2}-12x+30=30\) are \(x_{1}=0\) and \(x_{2}=12\), with \(x_{1}
Answered by UpStudy AI and reviewed by a Professional Tutor
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Beyond the Answer
To find the solutions by completing the square, we start with the equation \( x^{2} - 12x + 30 = 30 \). First, we simplify it to \( x^{2} - 12x = 0 \). Now, we take the coefficient of \( x \), which is -12, halve it to get -6, and square it to get 36. Then, we rewrite the equation as \( x^{2} - 12x + 36 = 36 \). This can be factored as \( (x - 6)^{2} = 36 \). Taking the square root of both sides gives us \( x - 6 = 6 \) or \( x - 6 = -6 \), leading to the solutions \( x_{1} = 0 \) and \( x_{2} = 12 \). So, \( x_{1} = 0 \) and \( x_{2} = 12 \).
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