Question
Two pools are being filled with water. To start, the first pool had 819 liters of water and the second pool was empty. Water is being added to the first pool at a rate of 18 liters per minute. Water is being added to the second pool at a rate of 39 liters per minute. Let \( x \) be the number of minutes water has been added. (a) For each pool, write an expression for the amount of water in the pool after \( x \) minutes. Amount of water in the first pool (in liters) Amount of water in the second pool (in liters) (b) Write an equation to show when the two pools would have the same amount of water.
Ask by Bowman Logan. in the United States
Feb 27,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
(a) First pool: 819 + 18x liters
Second pool: 39x liters
(b) 819 + 18x = 39x
Solution
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Mind Expander
After \( x \) minutes, the first pool will have an amount of water equal to \( 819 + 18x \) liters, while the second pool, starting empty, will have \( 39x \) liters. So, the amount of water in the first pool is \( 819 + 18x \) liters, and in the second pool, it’s simply \( 39x \) liters. To find out when both pools will have the same amount of water, you can set their expressions equal to each other: \[ 819 + 18x = 39x \]. Now, solve for \( x \) to find out after how many minutes the two pools will contain the same volume of water!
