Question
upstudy study bank question image url

A child has nine coins with a total value of 116 cents. What coins does the child have? (Hint: Make an orderly list of the nickels, dimes, pennies, and quarters.) The child has \( \square \) pennies, \( \square \) nickels, \( \square \) dimes and \( \square \) quarters.

Ask by Davison Todd. in the United States
Feb 27,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The child has 1 penny, 2 nickels, 3 dimes, and 3 quarters.

Solution

Let p be the number of pennies (1¢ each), n the number of nickels (5¢), d the number of dimes (10¢), and q the number of quarters (25¢). We have two conditions: 1) Total coins:   p + n + d + q = 9 2) Total value in cents:   1·p + 5·n + 10·d + 25·q = 116 Step 1. Express p from the coin count:   p = 9 – (n + d + q) Step 2. Substitute p into the value equation:   (9 – (n+d+q)) + 5n + 10d + 25q = 116 Simplify the equation:   9 – n – d – q + 5n + 10d + 25q = 116   9 + 4n + 9d + 24q = 116 Subtract 9 from both sides:   4n + 9d + 24q = 107 Step 3. Solve for nonnegative integers n, d, and q. It’s easiest to try small values for q. Let’s test q = 3:   4n + 9d + 24·3 = 107   4n + 9d + 72 = 107 Subtract 72:   4n + 9d = 35 Now we need to find nonnegative integers n and d such that 4n + 9d = 35. Check for d = 3:   4n + 9·3 = 4n + 27 = 35   4n = 8   n = 2 Now, plug n, d, and q back into the coin count equation:   p = 9 – (2 + 3 + 3) = 9 – 8 = 1 Step 4. Verification: - Pennies: 1 coin = 1¢ - Nickels: 2 coins = 2×5 = 10¢ - Dimes: 3 coins = 3×10 = 30¢ - Quarters: 3 coins = 3×25 = 75¢   Total value = 1 + 10 + 30 + 75 = 116¢   Total coins = 1 + 2 + 3 + 3 = 9 Everything checks out. Final answer: The child has 1 penny, 2 nickels, 3 dimes, and 3 quarters.

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

The Deep Dive

To solve this fun little puzzle, we can set up some equations! Let's represent the number of each type of coin: let \( p \) be pennies, \( n \) be nickels, \( d \) be dimes, and \( q \) be quarters. We know: 1. The total number of coins is 9: \( p + n + d + q = 9 \) 2. The total value of the coins is 116 cents: \( p + 5n + 10d + 25q = 116 \) Now, through some creative guess and check, we can find a combination! One valid example is having 6 pennies, 1 nickel, 1 dime, and 1 quarter. This sums up to \( 6 + 1 + 10 + 25 = 116 \) cents perfectly while keeping the total number of coins at 9. So, the child has 6 pennies, 1 nickel, 1 dime, and 1 quarter! Now, let’s have some fun solving this together: you just turned coins into math magic! For further exploration, if you're curious about currency understanding, dive into the fascinating history of coins! Many coins that we use today have tales that date back thousands of years, originating from ancient civilizations that created them as a means of trade. Those shiny little pieces hold stories of commerce and cultural evolution! Plus, if you're ever faced with similar problems, remember the key is to break down the information systematically! Often, starting with small values (like pennies) can help give a clearer picture before mixing in larger denominations. It's like piecing together a jigsaw puzzle to reveal a vibrant picture!

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy