Question
upstudy study bank question image url

Continuous Probability Distribution \[ \begin{array}{l}\text { Discussion Topic } \\ \text { Question: Imagine you're responsible for quality control in a factory that produces metal rods with lengths uniformly } \\ \text { distributed between } 95 \mathrm{~cm} \text { and } 105 \mathrm{~cm} \text {. } \\ \text { 1. Probability calculation: What is the probability that a randomly selected rod measures between } 98 \mathrm{~cm} \text { and } 102 \mathrm{~cm} \text { ? } \\ \text { 2. Quality specification: If rods shorter than } 96 \mathrm{~cm} \text { or longer than } 104 \mathrm{~cm} \text { are considered defective, what proportion of } \\ \text { the production is expected to be defective? } \\ \text { 3. Process Adjustment: To reduce the defect rate, management is considering adjusting the production process to } \\ \text { produce rods uniformly distributed between } 97 \mathrm{~cm} \text { and } 103 \mathrm{~cm} \text {. How would this change impact the proportion of } \\ \text { defective rods? }\end{array} \]

Ask by Bowers Jimenez. in the United States
Feb 26,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

1. The chance a rod is between 98 cm and 102 cm is 40%. 2. Originally, 20% of rods are defective. 3. After adjusting, no rods are defective based on the new quality standards.

Solution

Let’s work through each part step by step. 1. Probability that a randomly selected rod measures between 98 cm and 102 cm:  • The rods are uniformly distributed between 95 cm and 105 cm. The total length of the interval is 105 – 95 = 10 cm.  • The interval of interest (98 cm to 102 cm) has a length of 102 – 98 = 4 cm.  • For a uniform distribution, the probability is proportional to the interval length:   Probability = (Length of the interval of interest) / (Total length) = 4/10 = 0.4 or 40%. 2. Proportion of production expected to be defective when rods shorter than 96 cm or longer than 104 cm are deemed defective:  • Defective if rod < 96 cm or rod > 104 cm.  • For rods less than 96 cm:   Interval from 95 cm to 96 cm, length = 96 – 95 = 1 cm.  • For rods greater than 104 cm:   Interval from 104 cm to 105 cm, length = 105 – 104 = 1 cm.  • Total defective length = 1 cm + 1 cm = 2 cm.  • Defective proportion = (Total defective length) / (Total interval length) = 2/10 = 0.2 or 20%. 3. Impact of adjusting the production process so that rods are uniformly distributed between 97 cm and 103 cm:  • New distribution interval is now from 97 cm to 103 cm, so the total length is 103 – 97 = 6 cm.  • Quality specification remains that rods are acceptable if they are between 96 cm and 104 cm (rods shorter than 96 or longer than 104 are defective).  • Notice that the new range [97, 103] lies completely within the acceptable range [96, 104].  • Therefore, under the new process, every rod produced falls within specification, and the defect rate becomes 0%. In summary: 1. The probability that a rod is between 98 cm and 102 cm is 40%. 2. Under the original process, 20% of the rods are expected to be defective. 3. With the adjusted process, none (0%) of the rods are defective relative to the 96–104 cm quality standard.

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

The Deep Dive

The probability of selecting a rod between 98 cm and 102 cm can be calculated using the formula for a uniform distribution. The total length of the rod range is 10 cm (from 95 cm to 105 cm). The length of the desired range (98 cm to 102 cm) is 4 cm. Thus, the probability is given by the length of the desired range divided by the total range: \( P(98 \leq X \leq 102) = \frac{4}{10} = 0.4 \) or 40%. To determine the proportion of defective rods, consider the ranges outside the specifications (less than 96 cm or greater than 104 cm). The uniform distribution has a total length of 10 cm; the lengths below 96 cm (from 95 to 96 cm, which is 1 cm) and above 104 cm (from 104 to 105 cm, also 1 cm) add up to a total of 2 cm considered defective. Therefore, the proportion of defectives is \( \frac{2}{10} = 0.2 \) or 20%. If the rods are adjusted to be uniformly distributed between 97 cm and 103 cm, the total range is now 6 cm. The defective ranges now encompass those under 96 cm (0 cm, since the minimum is 97 cm) and over 104 cm (0 cm, since the maximum is 103 cm). This means no rods fall into the defective category, leading to a defect rate of 0% and a much-improved quality control outcome!

Related Questions

Latest Probability Questions

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy