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Chional force Difference between the kinetic forlad frictional and 5 totic Actional force (4) box is placed on a rough surface, it has a normal sorce of 120 force of magnitude 20 m is applied to the cight and cannot m io box. Calculate the magnitude and the direction of tho ictional forces if the coefficiont of stotic frictional force is 0,2

Ask by Hart Brewer. in South Africa
Feb 25,2025

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Answer

The frictional force is 24 N to the left.

Solution

To calculate the magnitude and direction of the frictional forces acting on the box, we need to consider the normal force, the applied force, and the coefficient of static friction. Given: - Normal force (N) = 120 N - Applied force (F) = 20 N - Coefficient of static friction (μs) = 0.2 The frictional force (Ff) can be calculated using the formula: \[ F_f = \mu_s \times N \] Substitute the given values: \[ F_f = 0.2 \times 120 \] \[ F_f = 24 \, \text{N} \] The direction of the frictional force is opposite to the direction of the applied force. Since the applied force is to the right, the frictional force will be to the left. Therefore, the magnitude of the frictional force is 24 N, and its direction is to the left.

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The maximum static frictional force can be calculated using the formula: \( f_s = \mu_s \times N \), where \( \mu_s \) is the coefficient of static friction (0.2) and \( N \) is the normal force (120 N). So, \( f_s = 0.2 \times 120 = 24 \) N. This means that the maximum static friction opposing the applied force can be 24 N. Since the applied force of 20 N is less than the maximum static frictional force of 24 N, the box will not move. Thus, the magnitude of the frictional force acting on the box is equal to the applied force, which is 20 N acting in the opposite direction of the applied force (to the left).

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