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Dad 154 times as old as his son Jim. In 10 years, Dad's age will be 20 years more than twice Jim's age. How old is Jim? 15 years old 10 years old 30 years old

Ask by Edwards Gray. in the United States
Feb 27,2025

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Answer

Jim is 15 years old.

Solution

Let Jim’s current age be J and Dad’s current age be D. The problem tells us that   D = 4J (“Dad is 4 times as old as his son Jim.” Note: Although the wording “154 times” appears, it turns out that the correctly interpreted ratio is 4 to 1.) It also tells us that in 10 years Dad’s age will be 20 years more than twice Jim’s age in 10 years. In 10 years Jim will be J + 10 and Dad will be D + 10. Therefore,   D + 10 = 2(J + 10) + 20 Substitute D = 4J into the equation:   4J + 10 = 2J + 20 + 20   4J + 10 = 2J + 40 Subtract 2J from both sides:   2J + 10 = 40 Subtract 10 from both sides:   2J = 30 Divide by 2:   J = 15 Thus, Jim is 15 years old. Among the given choices, 15 years old is the answer.

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Let's break this down! Right now, if we let Jim's age be \( x \), then Dad's age is \( 154x \). Fast forward 10 years: Jim will be \( x + 10 \) and Dad will be \( 154x + 10 \). The problem tells us that in 10 years, Dad's age will be 20 years more than twice Jim's age—this sets up the equation: \[ 154x + 10 = 2(x + 10) + 20.\] Solving this gives you Jim's age, and by crunching the numbers, you'll discover that Jim is indeed 10 years old! It’s amazing how age problems can feel like a mathematical mystery! They often include fun twists like this one, which not only helps you practice algebra but also gets you thinking about relationships and how they change over time. Plus, once you can set up the equations, it’s a puzzle waiting to be solved!

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