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Solve for the unknown in each equation. \( \begin{array}{ll}\text { Ex 1) } x+15=47 & \text { Ex 2) } x+94=147\end{array} \)

Ask by Rowe Pena. in the United States
Feb 27,2025

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Tutor-Verified Answer

Answer

Ejercicio 1: x = 32 Ejercicio 2: x = 53

Solution

Ejercicio 1) x + 15 = 47 Restamos 15 a ambos lados: x = 47 − 15 = 32 Ejercicio 2) x + 94 = 147 Restamos 94 a ambos lados: x = 147 − 94 = 53 Las soluciones son: Ejercicio 1: x = 32 Ejercicio 2: x = 53.

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The Deep Dive

To solve for \(x\) in the first equation, subtract 15 from both sides: \(x + 15 - 15 = 47 - 15\) This simplifies to \(x = 32\). For the second equation, subtract 94 from both sides: \(x + 94 - 94 = 147 - 94\) This simplifies to \(x = 53\). So, the solutions are \(x = 32\) for the first equation and \(x = 53\) for the second one!

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