Question
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Solve the equation by using the quadiatic formula \( -5 x^{2}+x=-4 \)

Ask by Flynn Rose. in the United States
Feb 27,2025

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Tutor-Verified Answer

Answer

The solutions are \( x = -\frac{4}{5} \) and \( x = 1 \).

Solution

Solve the equation \( -5x^{2}+x=-4 \). Solve the quadratic equation by following steps: - step0: Solve by factoring: \(-5x^{2}+x=-4\) - step1: Move the expression to the left side: \(-5x^{2}+x+4=0\) - step2: Factor the expression: \(\left(-x+1\right)\left(5x+4\right)=0\) - step3: Separate into possible cases: \(\begin{align}&-x+1=0\\&5x+4=0\end{align}\) - step4: Solve the equation: \(\begin{align}&x=1\\&x=-\frac{4}{5}\end{align}\) - step5: Rewrite: \(x_{1}=-\frac{4}{5},x_{2}=1\) The solutions to the equation \( -5x^{2}+x=-4 \) using the quadratic formula are: 1. \( x_{1} = -\frac{4}{5} \) 2. \( x_{2} = 1 \)

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Beyond the Answer

First, let's rearrange the equation to standard form: \( -5x^2 + x + 4 = 0 \). Now, we can apply the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Here, \( a = -5 \), \( b = 1 \), and \( c = 4 \). Plugging in these values gives \( x = \frac{-1 \pm \sqrt{1^2 - 4(-5)(4)}}{2(-5)} \). Simplifying this further leads to \( x = \frac{-1 \pm \sqrt{1 + 80}}{-10} \), resulting in \( x = \frac{-1 \pm 9}{-10} \), giving you the solutions \( x = \frac{-10}{-10} = 1 \) and \( x = \frac{8}{-10} = -0.8 \). Now, let’s do a quick wrap-up: you can always check your solutions by plugging them back into the original equation to ensure both sides balance out. It’s like a little mathematical dance where both partners (your solutions) need to move harmoniously together. If you try \( x = 1 \) and \( x = -0.8 \), both satisfy the original equation, confirming you’ve hit the right moves!

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