20 Un commerciante vende un prodotto a euro 325 , ottenendo così un guadagno del \( 30 \% \) sul costo di acquisto. Determina: \( \begin{array}{ll}\text { a. il costo sostenuto per l'acquisto } & \text { euro } 250 \\ \text { b. il guadagno conseguito } & \text { euro } \\ \text { c. il prezzo di vendita da applicare invece per guadagnare il } 30 \% \text { del ricavo } & \text { euro } 312,50\end{array} \)

pters 9, 10, 11) Question 14 (3 points) - Nicklaus Company has a machine that cost \( \$ 88,000 \). - They decided to sell this machine on June 30,2020 . - The balance in the accumulated depreciation account on December 31,2019 after recording the - The annual depreciation was \( \$ 64,000 \). - The machine was sold for \( \$ 52,000 \). Using the straight line method, what was the amount of the gain or loss recorded at the time of the sale?

Suppose that \( \$ 10,970 \) is invested at an interest rate of \( 5.5 \% \) per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time \( t \), in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is \( \mathrm{P}(\mathrm{t})=10970 e^{0.055 t} \). (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any numbers in the equation.) b) The balance after 1 year is \( \$ 11,590.25 \). (Simplify your answers. Round to two decimal places as needed.) The balance after 2 years is \( \$ \square \). (Simplify your answers. Round to two decimal places as needed.)

Previous Page Next Page 12 of 13 Question 19 ( 2 points) On January 1,2020 , Samwise COmpany issued \( ¥ 6,000,000,11 \%, 10 \) year bonds at face value. Interest is payable annually on January1. Prepare the journal entry to record the accrual of interest on December 31,2020 .

interes simple uso de porcentaje UN EMPLEADO RECIBE EN MAYO UN AUMENTO DEL 10\% SOBRE EL SUELDO DE MAYO PASANDO A GANAR 363 ¿CUANTO GANABA EN ABRIL?

En una empresa, el índice de rentabilidad ( \( r \) ) de un proyecto está dado por: \[ r=5 \cdot \log \left(\frac{t}{i}\right) \] Donde \( i \) es el dinero invertido en el proyecto y \( t \) es el dinero recibido al final del proyecto. Si para el proyecto se invierte \( \$ 1000000 \) y se obtiene una rentabilidad igual a 5 , ¿qué expresión permite determinar el dinero \( t \) que se recibirá al finalizar el proyecto? A) \( 6=5 \cdot \log t+30 \) B) \( 6=5 \cdot \log t-11 \) C) \( 6=5 \cdot \log t-25 \) D) \( 6=5 \cdot \log t-30 \)