2. Use the list of data to make a box plot what is the tgis? \[ 5,8,1,3,5,11,5,8,4 \]

72. Use the list of data to make a box plot. What is the IQR? \[ 5,8,1,3,5,11,6,8,4 \]

What is a scatter plot?

Out of 500 households sampled, 190 had kids under 18 living at home. Assuming the conditions are met, use the theoretical formula to construct a(n) \( 90 \% \) confidence interval for the true population proportion of households with kids under 18 living at home. a. Give your theoretical confidence interval in decimal form. Use 4 decimal places in your calculations and round your answers to four decimal places. ( \( 0.334,0.415 \) ) b. Interpret the confidence interval in context: We are \( 90 \% \) confident that the proportion of households with kids Show your formula and steps on paper or in the add work box (don't skip the between \( 34.43 \% \) and \( 41.57 \% \). interpretation above):

Based on past experience, a bank believes that \( 9 \% \) of the people who receive loans will not make their payments on time. The bank has recently approved 200 loans. a. Write about and check each of the conditions needed in the context of this situation to use the sampling distribution for the proportion of people who will not make their payments on time (Central Limit Theorem). Conditions: distritution for the proportion of people who make their payment on time based on the cental limit theorem. we can proceeds to analyze the proportion of the sameple that does not make payment on time using normal approximation methods. What are the mean and standard deviation of this model? b. Mean = 18 c. Standard deviation (accurate to 4 decimal places) \( =4.047 \) d. What is the probability that \( 10 \% \) or more of these clients will not make timely payments to 4 decimal places? 0.312 .

Reading proficiency: An educator wants to construct a \( 99.8 \% \) confidence interval for the proportion of elementary school children in Colorado who are proficient in reading. Part: \( \mathbf{0} / \mathbf{3} \) Part 1 of 3 (a) The results of a recent statewide test suggested that the proportion is 0.71 . Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.05 ? A sample of \( \square \) elementary school children is needed to obtain a \( 99.8 \% \) confidence interval with a margin of error of 0.05 .