Use common bases to solve the logarithmic equation \( \log _{3}\left(x^{2}-20\right)=\log _{3}(2 x+4) \). If necessary, round your answers to the nearest hundredth. One solution at \( x= \) Extraneous solution at \( \boldsymbol{x}= \)

\( 0.2 x+100=0 \) is

justifiant votre riponse \( \mathrm{A}^{\prime \prime}=-2^{3} \times(-5)^{2} \) \( B^{\prime \prime}=\left(\frac{2}{-3}\right)^{4} \times\left(-\frac{1}{2}\right)^{7} \times(-1)^{135} \) \( C^{\prime \prime}=-(-4)^{3} \times(-7)^{11} \) \( D^{\prime \prime}=\frac{-5^{2} \times(-3)^{3}}{-\left(-7^{2}\right)^{5}} \)

APPLCATION 03 Déterminer le signe des puissances suivantes en justifiant votre réponse, \( \mathrm{A}^{\prime \prime}=-2^{3} \times(-5)^{2} \) \( \mathrm{~B}^{\prime \prime}=\left(\frac{2}{-3}\right)^{4} \times\left(-\frac{1}{2}\right)^{7} \times(-1)^{135} \) \( \mathrm{C}^{\prime \prime}=-(-4)^{3} \times(-7)^{11} \) \( \mathrm{D}^{\prime \prime}=\frac{-5^{2} \times(-3)^{3}}{-\left(-7^{2}\right)^{5}} \)

\( 5 \frac { - \frac { 7 } { 5 } + \frac { 3 } { 4 } + \frac { 7 } { 60 } - \frac { 2 } { 15 } } { ( - 1 ) : ( \frac { 17 } { 12 } - \frac { 14 } { 5 } + \frac { 1 } { 3 } ) } \quad \frac { - \frac { 11 } { 6 } + \frac { 8 } { 3 } - \frac { 3 } { 4 } } { - \frac { 1 } { 3 } + \frac { 7 } { 4 } } \)

For which value of x does \( e^{x} = 7 \)?