The motion of a particle performing damped vibrations is given by $$ \gamma=e^{-t} \sin 2 t, \gamma $$ being the displacement trom its mean position at time $$ t $$. Show that $$ \gamma $$ is a maximum when $$ t=\frac{1}{2 an ^{-1}(2)} $$ and determine this maximum displacement to three significant figures.

Question

The motion of a particle performing damped vibrations is given by $$ \gamma=e^{-t} \sin 2 t, \gamma $$ being the displacement trom its mean position at time $$ t $$. Show that $$ \gamma $$ is a maximum when $$ t=\frac{1}{2 	an ^{-1}(2)} $$ and determine this maximum displacement to three significant figures.

Cross Romero · Accepted Answer

The maximum displacement occurs at $$ t=\frac{1}{2 	an ^{-1}(2)} $$ and is approximately 0.515.

Upstudy ThothAI Solution

Quick Answer

Step-by-step Solution

Upstudy ThothAI Solution

Quick Answer

Step-by-step Solution

Related Questions