Macdonald Brewer
07/27/2023 · Middle School

8. A spherical balloon is released from rest and expands as it Answer: rises. After rising for \( t \) seconds its radius is \( r \mathrm{~cm} \), and its \( 402 \mathrm{~cm}^{2} / \mathrm{s} \) surface area is \( A \mathrm{~cm}^{2} \), where \( A=4 \pi r^{2} \). The initial radius of the balloon is 16 cm . Given that the rate of increase of the radius is constant and has the value \( 0.8 \mathrm{~cm} \mathrm{~s}^{-1} \), find the rate of increase of \( A \) when \( t=5 \).

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The rate of increase of the surface area \( A \) when \( t = 5 \) seconds is approximately \( 402.12 \, \text{cm}^2/\text{s} \).

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