Topic
Q:
Find the time it takes for \( \$ 6,400 \) to double when invested at an annual interest rate of \( 2 \% \), compounded
continuously.
years
Find the time it takes for \( \$ 640,000 \) to double when invested at an annual interest rate of \( 2 \% \), compounded
continuously.
years
Q:
Find the time it takes for \( \$ 6,400 \) to double when invested at an annual interest rate of \( 2 \% \), compounded
continuously.
years
Find the time it takes for \( \$ 640,000 \) to double when invested at an annual interest rate of \( 2 \% \), compounde
continuously.
years
Q:
1.2 Which one of the following refers to expenditure measured in constant prices after
taking account of inflation:
a) Real expenditure.
b) Revenue.
c) Expenditure ceiling.
d) Government final consumption spending.
e) All of the above.
Q:
Find the time required for an investment of 5000 dollars to grow to 7200 dollars at an interest rate of 7.5
percent per year, compounded quarterly.
Your answer is \( t=\square \) years.
You may enter the exact value or round to 2 decimal places.
Q:
A person invest in an account with interest compounded continuously according to the formula
\( A=f(t)=7800 e^{0.043 t} \)
where \( A \) is the amount in the account and \( t \) is in years.
Find
\( f(0)=\$ 7800 \)
To the nearest cent, find the amount in the account after 4 years.
\( \$ 9261.06 \)
To the nearest tenth of a year, determine how long it will take for the investment to grow to \( \$ 14900 \).
Q:
Jerome will be buying a used car for \( \$ 7,000 \) in 3 years. How much money should he ask his parents for now so that, if he invests it at \( 7 \% \) compounded continuously,
he will have enough to buy the car?
Jerome should ask for \( \$ \square \).
(Round to the nearest cent as needed.)
Q:
You have \( \$ 2,500 \) on a credit card that charges a \( 19 \% \)
interest rate. If you want to pay off the credit card in 5
years, how much will you need to pay each month
(assuming you don't charge anything new to the card)?
Q:
A person invest in an account with interest compounded continuously according to the formula
\( A=f(t)=8200 e^{0.059 t} \)
where \( A \) is the amount in the account and \( t \) is in years.
Find
\( f(0)=\$ 8200 \)
To the nearest cent, find the amount in the account after 8 years.
\( \$ \) To the nearest tenth of a year, determine how long it will take for the investment to grow to \( \$ 10100 \).
Q:
How long does it take for an investment to double in value if it is invested at \( 7 \% \) compounded continuously?
At \( 7 \% \) compounded continuously, the investment doubles in about \( \square \) years.
(Round to two decimal places as needed.)
Q:
A person invest in an account with interest compounded continuously according to the formula
\( A=f(t)=8200 e^{0.059 t} \)
where \( A \) is the amount in the account and \( t \) is in years.
Find
\( f(0)=\$ \)
To the nearest cent, find the amount in the account after 8 years.
\( \$ \)
To the nearest tenth of a year, determine how long it will take for the investment to grow to \( \$ 10100 \).
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