Using the Law of Sines to solve the triangle if \( \angle A=37^{\circ}, \angle C=72^{\circ}, b=12: \) \( \angle B \) is 71 \( a=7.63 \) \( c=\square \) degrees; Round to two decimal places if needed. Assume \( \angle A \) is opposite side \( a, \angle B \) is opposite side \( b \), and \( \angle C \) is opposite side \( c \).

\( \frac { \sin A } { 1 + \cos A } + \frac { 1 - \operatorname { cosec } A } { \sin A } = 2 \operatorname { cosec } A \)

\begin{tabular}{l} (b) Using the formula \( \operatorname{Sin} 2 A=2 \operatorname{Sin} A \operatorname{Cos} A \) \\ solve the equation \( \sin 2 x-\cos x=0 \) \\ in the interval \( 0^{\circ} \leq x \leq 360^{\circ} \) \\ \hline\end{tabular}

\begin{tabular}{l} Resoluer el siguiente triangub. \\ \hline \( 5^{\circ} \) \\ \( \sin \alpha \)\end{tabular}\( \frac{B}{\operatorname{sen} \beta} \)

If \( \theta=-\frac{2 \pi}{3} \), then find exact values for the following: \( \sin (\theta)=\square \) \( \cos (\theta)=\square \) \( \tan (\theta)=\square \) \( \csc (\theta)=\square \) \( \sec (\theta)=\square \) \( \cot (\theta)=\square \)

Without using a calculator, compute the sine and cosine of \( 120^{\circ} \) by using the reference angle. What is the reference angle? \( \square \) degrees. In what quadrant is this angle? \( \square \) (answer \( 1,2,3 \), or 4 )