In un riferimento cartesiano disegna un parallelogramma che ha come vertici \( A(1 ; 2) \), \( B(7 ; 2), C(6 ; 6), D(0 ; 6) \). Calcola l'area del parallelogramma assu- mendo come unità di misura il centimetro

\( \left. \begin{array} { l } { \frac { ( 1 - h ) ^ { 2 } } { a ^ { 2 } } + \frac { ( y - k ) ^ { 2 } } { b ^ { 2 } } = 1 } \\ { \frac { h ^ { 2 } } { a ^ { 2 } } + \frac { [ ( 3 - \frac { \pi } { 2 } ) - k ] ^ { 2 } } { b ^ { 2 } } = 1 } \\ { \frac { ( - 1 - h ) ^ { 2 } } { a ^ { 2 } } + \frac { ( 1 - k ) ^ { 2 } } { b ^ { 2 } } = 1 } \\ { \frac { ( - 5 - h ) ^ { 2 } } { a ^ { 2 } } + \frac { ( 3 - k ) ^ { 2 } } { b ^ { 2 } } = 1 } \end{array} \right. \)

In \( \triangle \mathrm{TUV}, u=750 \mathrm{~cm}, v=670 \mathrm{~cm} \) and \( \angle \mathrm{T}=160^{\circ} \). Find the length of \( t \), to the nearest centimeter.

In \( \triangle \mathrm{TUV}, u=4.8 \mathrm{~cm}, v=4.4 \mathrm{~cm} \) and \( \angle \mathrm{T}=84^{\circ} \). Find the length of \( t \), to the nearest 1oth of a centimeter.

In \( \triangle \mathrm{EFG}, e=880 \) inches, \( f=140 \) inches and \( g=890 \) inches. Find the measure of \( \angle \mathrm{G} \) to the nearest 10th of a degree.

In \( \triangle \mathrm{UVW}, u=76 \) inches, \( v=27 \) inches and \( w=83 \) inches. Find the measure of \( \angle \mathrm{U} \) to the nearest 1oth of a degree.