Question 1 (Essay Worth 2 points) \( (01.02 \mathrm{HC}) \) Is the expression \( \mathrm{x}^{3} \cdot \mathrm{x}^{3} \cdot \mathrm{x}^{3} \) equivalent to \( \mathrm{x}^{3} \cdot 3 \cdot 3 \) ? Why or why not? Explain your reasoning.

\( \left.\begin{array}{l}\text { Solve the system of equations }-6 x-5 y=-8 \text { and } 3 x+2 y=2 \text { by } \\ \text { combining the equations. } \\ \qquad \begin{array}{rl}(-6 x-5 y=-8) \\ (3 x+2 y=2)\end{array} \\ -6 x-5 y=-8 \\ 3 x+2 y=2\end{array}\right) \)

\( ( 6,4 ) \quad \left\{ \begin{array} { l } { y = \frac { 3 } { 2 } x - 5 } \\ { y = x - 10 } \end{array} \right. \)

47. Encuentra el rango de valores para, que satisface las siguientes desigualdades. \( x-1<0 \) \( 3 \leq x+5 \) A) \( -2<x \leq 1 \) B) \( -1 \leq x<2 \) C) \( -2<x \leq-1 \) D) \( -2 \leq x<1 \)

\( ( 4,9 ) \quad \left\{ \begin{array} { l } { y = \frac { 3 } { 4 } x + 6 } \\ { 4 x - y = 7 } \end{array} \right. \)

Diberi fungsi \( f \) ditakrifkan sebagai \( f(x)=\frac{k+x}{2+3 x}, x \neq p \), dengan keadaan \( k \) dan \( p \) ialah pemalar. Given the function \( f \) is defined by \( f(x)=\frac{k+x}{2+3 x}, x \neq p \), such that \( k \) and \( p \) are constant. Cari / Find (a) nilai bagi \( p \), the value of \( p \), (b) nilai \( k \) jika \( f(1) \) memetakan kepada diri sendiri, value of \( k \) if \( f(1) \) maps onto itself, (c) \( f^{-1}(x) \), dan seterusnya cari julat \( f^{-1}(x) \) untuk domain \( 1 \leq x \leq 3 \). \( \quad f^{-1}(x) \), and hence find the range of \( f^{-1}(x) \) for the domain \( 1 \leq x \leq 3 \). [4arkah markah apan / Answer: