Given: $$ 36=x+4 x^{2}+8 $$, find $$ a, b $$, and $$ c $$. $$ \begin{array}{l} ext { a. } a=1, b=4, c=-28 \ ext { b. } a=1, b=4, c=8 \ ext { c. } a=-3, b=1, c=8 \ ext { d. } a=4, b=1, c=-28\end{array} $$

Question

Given: $$ 36=x+4 x^{2}+8 $$, find $$ a, b $$, and $$ c $$. $$ \begin{array}{l}	ext { a. } a=1, b=4, c=-28 \ 	ext { b. } a=1, b=4, c=8 \ 	ext { c. } a=-3, b=1, c=8 \ 	ext { d. } a=4, b=1, c=-28\end{array} $$

Simmons Matthews · Accepted Answer

The correct answer is d. $$ a=4, b=1, c=-28 $$.

Given: \( 36=x+4 x^{2}+8 \), find \( a, b \), and \( c \). \( \begin{array}{l}\text { a. } a=1, b=4, c=-28 \\ \text { b. } a=1, b=4, c=8 \\ \text { c. } a=-3, b=1, c=8 \\ \text { d. } a=4, b=1, c=-28\end{array} \)

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Given: \( 36=x+4 x^{2}+8 \), find \( a, b \), and \( c \). \( \begin{array}{l}\text { a. } a=1, b=4, c=-28 \\ \text { b. } a=1, b=4, c=8 \\ \text { c. } a=-3, b=1, c=8 \\ \text { d. } a=4, b=1, c=-28\end{array} \)

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Solución paso a paso

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