Fill in the blank so that the resulting statement is true. The first step in solving \( \frac{2}{x}-\frac{3}{y}=\frac{4}{z} \) for \( z \) is to multiply both sides of the equation by the least common denominator, which is

The following function is given. \( f(x)=3 x^{3}-7 x^{2}-75 x+175 \) a. List all rational zeros that are possible according to the Rational Zero Theorem. Choose the correct answer below.

1) \( \left(4 x^{2}+5\right)\left(x^{2}-2\right)\left(x^{2}+2\right)=0 \) A) \( \left\{\frac{i \sqrt{5}}{2},-\frac{i \sqrt{5}}{2}, \sqrt{2},-\sqrt{2}, i \sqrt{2},-i \sqrt{2}\right\} \) B) \( \left\{\frac{i \sqrt{10}}{2},-\frac{i \sqrt{10}}{2}, \sqrt{2},-\sqrt{2}, i \sqrt{2},-i \sqrt{2}\right\} \) C) \( \left\{\frac{i \sqrt{15}}{3},-\frac{i \sqrt{15}}{3}, i \sqrt{3},-i \sqrt{3}, i \sqrt{2},-i \sqrt{2}\right\} \) D) \( \left\{\right. \) mult. \( \left.2, \frac{i \sqrt{5}}{2},-\frac{i \sqrt{5}}{2}, \sqrt{2},-\sqrt{2}\right\} \)

\( \left.\begin{array}{l}\left.\text { 1) } \begin{array}{l}\left(4 x^{2}+5\right)\left(x^{2}-2\right)\left(x^{2}+2\right)=0 \\ \text { A) }\left\{\begin{array}{l}i \sqrt{5} \\ 2\end{array}-\frac{i \sqrt{5}}{2}, \sqrt{2},-\sqrt{2}, i \sqrt{2},-i \sqrt{2}\right. \\ \text { B) }\left\{\frac{i \sqrt{10}}{2},-\frac{i \sqrt{10}}{2}, \sqrt{2},-\sqrt{2}, i \sqrt{2},-i \sqrt{2}\right.\end{array}\right\} \\ \text { C) }\left\{\frac{i \sqrt{15}}{3},-\frac{i \sqrt{15}}{3}, i \sqrt{3},-i \sqrt{3}, i \sqrt{2},-i \sqrt{2}\right.\end{array}\right\} \)

dent Name: Which graph shows the solution of \( -6(n-1)<3 \) and \( 2(n+1)>0 \) ?

\( 1 \leftarrow \quad \) Given vectors \( \mathbf{u} \) and \( \mathbf{v} \), find (a) \( 7 \mathbf{u} \) \( \mathbf{u}=6 \mathbf{i}, \mathbf{v}=3 \mathbf{i}+6 \mathbf{j} \) (b) \( 7 \mathbf{u}+2 \mathbf{v} \) (c) \( \mathbf{v}-2 \mathbf{u} \). (a) \( 7 \mathbf{u}=42 \mathbf{i} \) (Type your answer in terms of iand \( \mathbf{j} \).) (b) \( 7 \mathbf{u}+2 \mathbf{v}=\square \) (Type your answer in terms of \( \mathbf{i} \) and \( \mathbf{j} \).)