Calculate the definite integral. $$ \int_{0}^{6}\left(x-\frac{1}{2}\right) d x $$ $$ \int_{0}^{6}\left(x-\frac{1}{2}\right) d x=\square $$ (Simplify your answer.)

Question

Mcfarlane Salinas · Accepted Answer

The definite integral $$ \int_{0}^{6}\left(x-\frac{1}{2}\right) dx $$ is equal to 15.

Calculate the definite integral. \( \int_{0}^{6}\left(x-\frac{1}{2}\right) d x \) \( \int_{0}^{6}\left(x-\frac{1}{2}\right) d x=\square \) (Simplify your answer.)

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Solución paso a paso

Calculate the definite integral. \( \int_{0}^{6}\left(x-\frac{1}{2}\right) d x \) \( \int_{0}^{6}\left(x-\frac{1}{2}\right) d x=\square \) (Simplify your answer.)

Solución ThothAI de Upstudy

Respuesta rápida

Solución paso a paso

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